No.6-8 Latihan Soal Termokimia Kimia 11 SMA

Soal 6

Diketahui
$\Delta H_f^\circ \text{CaCO}_3(s) = -1207\ \text{kJ mol}^{-1}$
$\Delta H_f^\circ \text{CaO}(s) = -635{,}5\ \text{kJ mol}^{-1}$
$\Delta H_f^\circ \text{CO}_2(g) = -394\ \text{kJ mol}^{-1}$

Tentukan perubahan entalpi pada proses peruraian CaCO₃ dengan reaksi:

$$\text{CaCO}_3(s) \rightarrow \text{CaO}(s) + \text{CO}_2(g)$$Pembahasan

Soal 7

Diketahui:

$$\text{HCN(aq)}\to {\text{H}}^{+}(aq)+{\text{CN}}^{-}(aq)\mathrm{\Delta }H=+\mathrm{42,8}\text{ kJ}$$$${\text{H}}_2\text{O}(l)\to {\text{H}}^{+}(aq)+{\text{OH}}^{-}(aq)\mathrm{\Delta }H=+\mathrm{53,2}\text{ kJ}$$

Hitunglah $\Delta H$ dari reaksi:

$$\text{HCN(aq)} + \text{OH}^-(aq) \rightarrow \text{H}_2\text{O}(l) + \text{CN}^-(aq)$$

Soal 8

Diketahui persamaan termokimia sebagai berikut:

$${\text{C}}_4{\text{H}}_9\text{OH}(l)+6{\text{O}}_2(g)\to 4{\text{CO}}_2(g)+5{\text{H}}_2\text{O}(g)\mathrm{\Delta }H=-2456\text{ kJ}$$$$({\text{C}}_2{\text{H}}_5{)}_2\text{O}(l)+6{\text{O}}_2(g)\to 4{\text{CO}}_2(g)+5{\text{H}}_2\text{O}(g)\mathrm{\Delta }H=-2510\text{ kJ}$$

Hitunglah perubahan entalpi untuk reaksi:

$$({\text{C}}_2{\text{H}}_5{)}_2\text{O}(l)\to {\text{C}}_4{\text{H}}_9\text{OH}(l)$$

Pembahasan

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